What are the solutions to the equation 1/10+2x+3/20+2x^2+x/2 =1 ?

The solutions to the equation 1/10+2x+3/20+2x^2+x/2 =1 are x= 1/4 ,x=-3/2

Find the zeros of 1/10+2x+3/20+2x^2+x/2 =1

The zeros of 1/10+2x+3/20+2x^2+x/2 =1 are x= 1/4 ,x=-3/2

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\frac{1}{10} + 2 x + \frac{3}{20} + 2 x^{2} + \frac{x}{2} = 1

x = \frac{1}{4}, x = - \frac{3}{2}

Solution steps

\frac{1}{10} + 2 x + \frac{3}{20} + 2 x^{2} + \frac{x}{2} = 1

Find Least Common Multiplier of

10, 20, 2 : 20

Multiply by LCM=

20

\frac{1}{10} \cdot 20 + 2 x \cdot 20 + \frac{3}{20} \cdot 20 + 2 x^{2} \cdot 20 + \frac{x}{2} \cdot 20 = 1 \cdot 20

Simplify

2 + 40 x + 3 + 40 x^{2} + 10 x = 20

40 x^{2} + 50 x + 5 = 20

Move

20

to the left side

40 x^{2} + 50 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 40 ( - 15 )}{2 \cdot 40}

5 0^{2} - 4 \cdot 40 (- 15) = 70

x_{1, 2} = \frac{- 50 \pm 70}{2 \cdot 40}

Separate the solutions

x_{1} = \frac{- 50 + 70}{2 \cdot 40}, x_{2} = \frac{- 50 - 70}{2 \cdot 40}

x = \frac{- 50 + 70}{2 \cdot 40} : \frac{1}{4}

x = \frac{- 50 - 70}{2 \cdot 40} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{3}{2}

- \frac{6}{7} + 8

u + 86 \geq 88

\frac{3}{1}

20 = r + 11

k^{2} - k - 2

What are the solutions to the equation 1/10+2x+3/20+2x^2+x/2 =1 ?
The solutions to the equation 1/10+2x+3/20+2x^2+x/2 =1 are x= 1/4 ,x=-3/2
Find the zeros of 1/10+2x+3/20+2x^2+x/2 =1
The zeros of 1/10+2x+3/20+2x^2+x/2 =1 are x= 1/4 ,x=-3/2