What are the solutions to the equation roots y=x^2+3x-10 ?

The solutions to the equation roots y=x^2+3x-10 are x=2,x=-5

Find the zeros of roots y=x^2+3x-10

The zeros of roots y=x^2+3x-10 are x=2,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

y = x^{2} + 3 x - 10

x = 2, x = - 5

Solution steps

x^{2} + 3 x - 10

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 7}{2 \cdot 1}, x_{2} = \frac{- 3 - 7}{2 \cdot 1}

x = \frac{- 3 + 7}{2 \cdot 1} : 2

x = \frac{- 3 - 7}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 2, x = - 5

32 = x^{5}

f (x) = x^{2} - 2 x - 3

Q u a d r a t i c (- 8.1)

8.5 oz

∣ x ∣ < 1

What are the solutions to the equation roots y=x^2+3x-10 ?
The solutions to the equation roots y=x^2+3x-10 are x=2,x=-5
Find the zeros of roots y=x^2+3x-10
The zeros of roots y=x^2+3x-10 are x=2,x=-5