What is factor 28a^2+5ab-12b^2 ?

The solution to factor 28a^2+5ab-12b^2 is (7a-4b)(4a+3b)

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factor 28a^2+5ab-12b^2

factor

28 a^{2} + 5 ab - 12 b^{2}

(7 a - 4 b) (4 a + 3 b)

Solution steps

28 a^{2} + 5 ab - 12 b^{2}

Break the expression into groups

= (28 a^{2} - 16 ab) + (21 ab - 12 b^{2})

Factor out

4 a

from

28 a^{2} - 16 ab : 4 a (7 a - 4 b)

Factor out

3 b

from

21 ab - 12 b^{2} : 3 b (7 a - 4 b)

= 4 a (7 a - 4 b) + 3 b (7 a - 4 b)

Factor out common term

7 a - 4 b

= (7 a - 4 b) (4 a + 3 b)

\frac{1}{4 π ( 3 + 2 ) ^{2}} (- 13)

- 27 = - 14 + p

\frac{g}{6} - 2 > - 1

(4 x)^{\frac{1}{2}} \cdot (9 x)^{\frac{1}{2}}

\frac{x}{3} = (4) (3)

What is factor 28a^2+5ab-12b^2 ?
The solution to factor 28a^2+5ab-12b^2 is (7a-4b)(4a+3b)