What are the solutions to the equation 3x^2-x-3=0 ?

The solutions to the equation 3x^2-x-3=0 are x=(1+sqrt(37))/6 ,x=(1-sqrt(37))/6

Find the zeros of 3x^2-x-3=0

The zeros of 3x^2-x-3=0 are x=(1+sqrt(37))/6 ,x=(1-sqrt(37))/6

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3 x^{2} - x - 3 = 0

x = \frac{1 + 37}{6}, x = \frac{1 - 37}{6}

Solution steps

3 x^{2} - x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 3) = 37

x_{1, 2} = \frac{- ( - 1 ) \pm 37}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 37}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 37}{2 \cdot 3}

x = \frac{- ( - 1 ) + 37}{2 \cdot 3} : \frac{1 + 37}{6}

x = \frac{- ( - 1 ) - 37}{2 \cdot 3} : \frac{1 - 37}{6}

The solutions to the quadratic equation are:

x = \frac{1 + 37}{6}, x = \frac{1 - 37}{6}

\frac{3}{4} \cdot 16

∣ x - 7 ∣ = - 1

(9 - 2 x)^{2} \leq (4 x)^{2}

x (b + c) + 3 b + 3 c

What are the solutions to the equation 3x^2-x-3=0 ?
The solutions to the equation 3x^2-x-3=0 are x=(1+sqrt(37))/6 ,x=(1-sqrt(37))/6
Find the zeros of 3x^2-x-3=0
The zeros of 3x^2-x-3=0 are x=(1+sqrt(37))/6 ,x=(1-sqrt(37))/6