What is the answer to 4(2x^2+1)-2(4x-1)=2|(2x-1)^2| ?

The answer to 4(2x^2+1)-2(4x-1)=2|(2x-1)^2| is No Solution for x\in\mathbb{R}

Solve for x: 4(2x^2+1)-2(4x-1)=2|(2x-1)^2|

The solution is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 (2 x^{2} + 1) - 2 (4 x - 1) = 2 (2 x - 1)^{2}

No Solution for x \in R

Solution steps

4 (2 x^{2} + 1) - 2 (4 x - 1) = 2 (2 x - 1)^{2}

Find positive and negative intervals

- \infty < x < \infty

Solve the inequality for each interval

No Solution for x \in R

x^{3} - 8 x^{2} + 15 x

\frac{3}{2} + (- \frac{6}{5})

3 (3 v - 8) = 21

\frac{1}{8} = \frac{2}{5} x

72 \cdot 4

What is the answer to 4(2x^2+1)-2(4x-1)=2|(2x-1)^2| ?
The answer to 4(2x^2+1)-2(4x-1)=2|(2x-1)^2| is No Solution for x\in\mathbb{R}
Solve for x: 4(2x^2+1)-2(4x-1)=2|(2x-1)^2|
The solution is No Solution for x\in\mathbb{R}