What are the solutions to the equation 5y^2+20=0 ?

The solutions to the equation 5y^2+20=0 are y=2i,y=-2i

Find the zeros of 5y^2+20=0

The zeros of 5y^2+20=0 are y=2i,y=-2i

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5 y^{2} + 20 = 0

y = 2 i, y = - 2 i

Solution steps

5 y^{2} + 20 = 0

Move

20

to the right side

5 y^{2} = - 20

Divide both sides by

5

y^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 4, y = - - 4

- 4 = 2 i

- - 4 = - 2 i

y = 2 i, y = - 2 i

\frac{3}{4} x = 9

7 x + 11 > 25

\frac{0}{( 0 ) ^{2} + 1}

∣ x + 10 ∣ + 7 < 11

3.7 y - 31.5 - 1.9 y = 13.5

What are the solutions to the equation 5y^2+20=0 ?
The solutions to the equation 5y^2+20=0 are y=2i,y=-2i
Find the zeros of 5y^2+20=0
The zeros of 5y^2+20=0 are y=2i,y=-2i