What is the answer to (2y-1)/5-(y+3)/7 =0 ?

The answer to (2y-1)/5-(y+3)/7 =0 is y= 22/9

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(2y-1)/5-(y+3)/7 =0

\frac{2 y - 1}{5} - \frac{y + 3}{7} = 0

y = \frac{22}{9}

Solution steps

\frac{2 y - 1}{5} - \frac{y + 3}{7} = 0

Multiply by LCM

7 (2 y - 1) - 5 (y + 3) = 0

Expand

7 (2 y - 1) - 5 (y + 3) : 9 y - 22

9 y - 22 = 0

Move

22

to the right side

9 y = 22

Divide both sides by

9

y = \frac{22}{9}

0.45 m - 9 = 0.9 m

- - 32

(\frac{7}{8})^{2}

m^{2} - 18 m + 81

∣ 1 - 6 x ∣ - 9 < - 6

What is the answer to (2y-1)/5-(y+3)/7 =0 ?
The answer to (2y-1)/5-(y+3)/7 =0 is y= 22/9
Solve for y: (2y-1)/5-(y+3)/7 =0
The solution is y= 22/9