What are the solutions to the equation -3x^2-15x+72=0 ?

The solutions to the equation -3x^2-15x+72=0 are x=-8,x=3

Find the zeros of -3x^2-15x+72=0

The zeros of -3x^2-15x+72=0 are x=-8,x=3

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- 3 x^{2} - 15 x + 72 = 0

x = - 8, x = 3

Solution steps

- 3 x^{2} - 15 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 ( - 3 ) \cdot 72}{2 ( - 3 )}

(- 15)^{2} - 4 (- 3) \cdot 72 = 33

x_{1, 2} = \frac{- ( - 15 ) \pm 33}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 33}{2 ( - 3 )}, x_{2} = \frac{- ( - 15 ) - 33}{2 ( - 3 )}

x = \frac{- ( - 15 ) + 33}{2 ( - 3 )} : - 8

x = \frac{- ( - 15 ) - 33}{2 ( - 3 )} : 3

The solutions to the quadratic equation are:

x = - 8, x = 3

7 x^{4} - 343 y^{4}

- \frac{4}{7} \cdot 2

(4 x^{\frac{1}{2}})^{2}

\frac{b ^{2} - ab}{a - b}

4 - ∣ 3 x + 6 ∣ = 1

What are the solutions to the equation -3x^2-15x+72=0 ?
The solutions to the equation -3x^2-15x+72=0 are x=-8,x=3
Find the zeros of -3x^2-15x+72=0
The zeros of -3x^2-15x+72=0 are x=-8,x=3