What are the solutions to the equation x^2-16x=23 ?

The solutions to the equation x^2-16x=23 are x=8+sqrt(87),x=8-sqrt(87)

Find the zeros of x^2-16x=23

The zeros of x^2-16x=23 are x=8+sqrt(87),x=8-sqrt(87)

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x^{2} - 16 x = 23

x = 8 + 87, x = 8 - 87

Decimal Notation

x = 17.32737 \dots, x = - 1.32737 \dots

Solution steps

x^{2} - 16 x = 23

Move

23

to the left side

x^{2} - 16 x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 23 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 23) = 287

x_{1, 2} = \frac{- ( - 16 ) \pm 2 87}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 87}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 2 87}{2 \cdot 1}

x = \frac{- ( - 16 ) + 2 87}{2 \cdot 1} : 8 + 87

x = \frac{- ( - 16 ) - 2 87}{2 \cdot 1} : 8 - 87

The solutions to the quadratic equation are:

x = 8 + 87, x = 8 - 87

\frac{2}{3} x - \frac{x}{4} = 1 + \frac{5 x}{6} + \frac{11}{12}

3 m^{4} - 243

- \frac{35}{2} (\frac{1}{100}) + \frac{35}{2}

x^{2} - 30 x + 200

x \leq - 6 and x > - 4

What are the solutions to the equation x^2-16x=23 ?
The solutions to the equation x^2-16x=23 are x=8+sqrt(87),x=8-sqrt(87)
Find the zeros of x^2-16x=23
The zeros of x^2-16x=23 are x=8+sqrt(87),x=8-sqrt(87)