What are the solutions to the equation x^2-2x=-1 ?

The solutions to the equation x^2-2x=-1 are x=1

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x^2-2x=-1

x^{2} - 2 x = - 1

x = 1

Solution steps

x^{2} - 2 x = - 1

Move

1

to the left side

x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 2 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 2 )}{2 \cdot 1}

\frac{- ( - 2 )}{2 \cdot 1} = 1

x = 1

The solution to the quadratic equation is:

x = 1

\frac{x - 2}{3 x + 5} \leq 4

- 5 x^{2} + 20 x = 0

\frac{m ^{5} + 3 m ^{4} - 2 m ^{3}}{2 m ^{3}}

x^{2} - 2 x y - 35 y^{2}

\frac{3 ( m ) ^{3}}{2 m ^{- 9}}

What are the solutions to the equation x^2-2x=-1 ?
The solutions to the equation x^2-2x=-1 are x=1
Find the zeros of x^2-2x=-1
The zeros of x^2-2x=-1 are x=1