What are the solutions to the equation 9x^2+9x-10=0 ?

The solutions to the equation 9x^2+9x-10=0 are x= 2/3 ,x=-5/3

Find the zeros of 9x^2+9x-10=0

The zeros of 9x^2+9x-10=0 are x= 2/3 ,x=-5/3

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9 x^{2} + 9 x - 10 = 0

x = \frac{2}{3}, x = - \frac{5}{3}

Solution steps

9 x^{2} + 9 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 9 ( - 10 )}{2 \cdot 9}

9^{2} - 4 \cdot 9 (- 10) = 21

x_{1, 2} = \frac{- 9 \pm 21}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 9 + 21}{2 \cdot 9}, x_{2} = \frac{- 9 - 21}{2 \cdot 9}

x = \frac{- 9 + 21}{2 \cdot 9} : \frac{2}{3}

x = \frac{- 9 - 21}{2 \cdot 9} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{5}{3}

u^{2} - 4

(\frac{4}{5} + \frac{3}{5}) + 3.5 \cdot 5

3 (x^{2} - 5 x - 6)

- 4 m - 2.7 > 4.1

\frac{2 x}{3} + 5 \leq \frac{5 x}{2} - 1

What are the solutions to the equation 9x^2+9x-10=0 ?
The solutions to the equation 9x^2+9x-10=0 are x= 2/3 ,x=-5/3
Find the zeros of 9x^2+9x-10=0
The zeros of 9x^2+9x-10=0 are x= 2/3 ,x=-5/3