What are the solutions to the equation 35^2+12^2=c^2 ?

The solutions to the equation 35^2+12^2=c^2 are c=37,c=-37

Find the zeros of 35^2+12^2=c^2

The zeros of 35^2+12^2=c^2 are c=37,c=-37

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3 5^{2} + 1 2^{2} = c^{2}

c = 37, c = - 37

Solution steps

3 5^{2} + 1 2^{2} = c^{2}

Switch sides

c^{2} = 3 5^{2} + 1 2^{2}

Simplify

3 5^{2} + 1 2^{2} : 1369

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 1369, c = - 1369

1369 = 37

- 1369 = - 37

c = 37, c = - 37

ln (\frac{1}{5})

3 ∣ 5 y - 1 ∣ - 5 = 4

\frac{18}{21 m + 6}

\frac{1}{9} \cdot \frac{1}{9}

- 2 \leq x

What are the solutions to the equation 35^2+12^2=c^2 ?
The solutions to the equation 35^2+12^2=c^2 are c=37,c=-37
Find the zeros of 35^2+12^2=c^2
The zeros of 35^2+12^2=c^2 are c=37,c=-37