What are the solutions to the equation (4-3x)^2-64=0 ?

The solutions to the equation (4-3x)^2-64=0 are x=-4/3 ,x=4

Find the zeros of (4-3x)^2-64=0

The zeros of (4-3x)^2-64=0 are x=-4/3 ,x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(4 - 3 x)^{2} - 64 = 0

x = - \frac{4}{3}, x = 4

Decimal Notation

x = - 1.33333 \dots, x = 4

Solution steps

(4 - 3 x)^{2} - 64 = 0

Move

64

to the right side

(4 - 3 x)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 - 3 x = 64 : x = - \frac{4}{3}

Solve

4 - 3 x = - 64 : x = 4

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = 4

2 x^{2} - 3 x - 35

x - x^{3} \geq 0

23 \cdot 2.8 \cdot X^{2} - 175 \cdot X - 6 \cdot 45 = 0

5 z + 2 = 2 z + 5

(x y)^{- 1} (x^{- 1} + y^{- 1})^{- 1}

What are the solutions to the equation (4-3x)^2-64=0 ?
The solutions to the equation (4-3x)^2-64=0 are x=-4/3 ,x=4
Find the zeros of (4-3x)^2-64=0
The zeros of (4-3x)^2-64=0 are x=-4/3 ,x=4