What are the solutions to the equation -Q^2+18Q-25=0 ?

The solutions to the equation -Q^2+18Q-25=0 are Q=9-2sqrt(14),Q=9+2sqrt(14)

Find the zeros of -Q^2+18Q-25=0

The zeros of -Q^2+18Q-25=0 are Q=9-2sqrt(14),Q=9+2sqrt(14)

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- Q^{2} + 18 Q - 25 = 0

Q = 9 - 214, Q = 9 + 214

Decimal Notation

Q = 1.51668 \dots, Q = 16.48331 \dots

Solution steps

- Q^{2} + 18 Q - 25 = 0

Solve with the quadratic formula

Q_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 ( - 1 ) ( - 25 )}{2 ( - 1 )}

1 8^{2} - 4 (- 1) (- 25) = 414

Q_{1, 2} = \frac{- 18 \pm 4 14}{2 ( - 1 )}

Separate the solutions

Q_{1} = \frac{- 18 + 4 14}{2 ( - 1 )}, Q_{2} = \frac{- 18 - 4 14}{2 ( - 1 )}

Q = \frac{- 18 + 4 14}{2 ( - 1 )} : 9 - 214

Q = \frac{- 18 - 4 14}{2 ( - 1 )} : 9 + 214

The solutions to the quadratic equation are:

Q = 9 - 214, Q = 9 + 214

(a + b)^{- 1}

2 (2) + 4

a - 3 = 9

\frac{2}{4 + 6} - \frac{2}{4 - 6}

5 x^{2} + 14 x - 3

What are the solutions to the equation -Q^2+18Q-25=0 ?
The solutions to the equation -Q^2+18Q-25=0 are Q=9-2sqrt(14),Q=9+2sqrt(14)
Find the zeros of -Q^2+18Q-25=0
The zeros of -Q^2+18Q-25=0 are Q=9-2sqrt(14),Q=9+2sqrt(14)