What are the solutions to the equation (x^2)/4-x/1 = 5/4 ?

The solutions to the equation (x^2)/4-x/1 = 5/4 are x=5,x=-1

Find the zeros of (x^2)/4-x/1 = 5/4

The zeros of (x^2)/4-x/1 = 5/4 are x=5,x=-1

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\frac{x ^{2}}{4} - \frac{x}{1} = \frac{5}{4}

x = 5, x = - 1

Solution steps

\frac{x ^{2}}{4} - \frac{x}{1} = \frac{5}{4}

Multiply both sides by

4

x^{2} - 4 x = 5

Move

5

to the left side

x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

x = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

15 x + 28 = 27 x + 4

- x^{2} = 0

169 = (x - 7)^{2}

(a^{8})^{\frac{3}{2}}

∣ - 2 x + 3 ∣ \leq 11

What are the solutions to the equation (x^2)/4-x/1 = 5/4 ?
The solutions to the equation (x^2)/4-x/1 = 5/4 are x=5,x=-1
Find the zeros of (x^2)/4-x/1 = 5/4
The zeros of (x^2)/4-x/1 = 5/4 are x=5,x=-1