What are the solutions to the equation 3m+58=m^2+12m+36 ?

The solutions to the equation 3m+58=m^2+12m+36 are m=2,m=-11

Find the zeros of 3m+58=m^2+12m+36

The zeros of 3m+58=m^2+12m+36 are m=2,m=-11

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3 m + 58 = m^{2} + 12 m + 36

m = 2, m = - 11

Solution steps

3 m + 58 = m^{2} + 12 m + 36

Switch sides

m^{2} + 12 m + 36 = 3 m + 58

Move

58

to the left side

m^{2} + 12 m - 22 = 3 m

Move

3 m

to the left side

m^{2} + 9 m - 22 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 22 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 22) = 13

m_{1, 2} = \frac{- 9 \pm 13}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 9 + 13}{2 \cdot 1}, m_{2} = \frac{- 9 - 13}{2 \cdot 1}

m = \frac{- 9 + 13}{2 \cdot 1} : 2

m = \frac{- 9 - 13}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

m = 2, m = - 11

- (2 - 3 x) < 5 (4 - x)

- 3 (3 c + 5) = 2 (10 - c)

0.6 x - 0.3 = 0.1

9 x^{2} + 30 x + 16

6 x^{2} - 11 x - 10 = 0

What are the solutions to the equation 3m+58=m^2+12m+36 ?
The solutions to the equation 3m+58=m^2+12m+36 are m=2,m=-11
Find the zeros of 3m+58=m^2+12m+36
The zeros of 3m+58=m^2+12m+36 are m=2,m=-11