What are the solutions to the equation 4x^2+9x-2=0 ?

The solutions to the equation 4x^2+9x-2=0 are x=(-9+sqrt(113))/8 ,x=(-9-sqrt(113))/8

Find the zeros of 4x^2+9x-2=0

The zeros of 4x^2+9x-2=0 are x=(-9+sqrt(113))/8 ,x=(-9-sqrt(113))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 9 x - 2 = 0

x = \frac{- 9 + 113}{8}, x = \frac{- 9 - 113}{8}

Decimal Notation

x = 0.20376 \dots, x = - 2.45376 \dots

Solution steps

4 x^{2} + 9 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

9^{2} - 4 \cdot 4 (- 2) = 113

x_{1, 2} = \frac{- 9 \pm 113}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 9 + 113}{2 \cdot 4}, x_{2} = \frac{- 9 - 113}{2 \cdot 4}

x = \frac{- 9 + 113}{2 \cdot 4} : \frac{- 9 + 113}{8}

x = \frac{- 9 - 113}{2 \cdot 4} : \frac{- 9 - 113}{8}

The solutions to the quadratic equation are:

x = \frac{- 9 + 113}{8}, x = \frac{- 9 - 113}{8}

\frac{x + 1}{2} = 3

\frac{3 - 10 i}{5 i}

2 x^{3} + 11 x^{2} - 20 x + 7

- 4 \leq 4 x + 4 \leq 8

7 (5) - 4 (1) = - 5

What are the solutions to the equation 4x^2+9x-2=0 ?
The solutions to the equation 4x^2+9x-2=0 are x=(-9+sqrt(113))/8 ,x=(-9-sqrt(113))/8
Find the zeros of 4x^2+9x-2=0
The zeros of 4x^2+9x-2=0 are x=(-9+sqrt(113))/8 ,x=(-9-sqrt(113))/8