What are the solutions to the equation x^2+3x+8=-3x+3 ?

The solutions to the equation x^2+3x+8=-3x+3 are x=-1,x=-5

Find the zeros of x^2+3x+8=-3x+3

The zeros of x^2+3x+8=-3x+3 are x=-1,x=-5

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x^{2} + 3 x + 8 = - 3 x + 3

x = - 1, x = - 5

Solution steps

x^{2} + 3 x + 8 = - 3 x + 3

Move

3

to the left side

x^{2} + 3 x + 5 = - 3 x

Move

3 x

to the left side

x^{2} + 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 5 = 4

x_{1, 2} = \frac{- 6 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4}{2 \cdot 1}, x_{2} = \frac{- 6 - 4}{2 \cdot 1}

x = \frac{- 6 + 4}{2 \cdot 1} : - 1

x = \frac{- 6 - 4}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 1, x = - 5

- \frac{1}{4} x - 1 \leq - 9

4 x^{2} - 36 x = - 93

lo g_{8} (3 x + 7) < lo g_{8} (7 x + 4)

6 x^{2} - 23 x - 4

\frac{4 ^{5}}{4 ^{2}}

What are the solutions to the equation x^2+3x+8=-3x+3 ?
The solutions to the equation x^2+3x+8=-3x+3 are x=-1,x=-5
Find the zeros of x^2+3x+8=-3x+3
The zeros of x^2+3x+8=-3x+3 are x=-1,x=-5