What are the solutions to the equation (50+3x^2)/5 =x^2 ?

The solutions to the equation (50+3x^2)/5 =x^2 are x=5,x=-5

Find the zeros of (50+3x^2)/5 =x^2

The zeros of (50+3x^2)/5 =x^2 are x=5,x=-5

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\frac{50 + 3 x ^{2}}{5} = x^{2}

x = 5, x = - 5

Solution steps

\frac{50 + 3 x ^{2}}{5} = x^{2}

Move

x^{2}

to the left side

\frac{50 - 2 x ^{2}}{5} = 0

Multiply both sides by

5

50 - 2 x^{2} = 0

Move

50

to the right side

- 2 x^{2} = - 50

Divide both sides by

- 2

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

(4 c^{4}) (a c^{3}) (3 a^{5} c)

x - 2 < 3

(y \cdot y^{\frac{1}{3}})^{\frac{3}{2}}

- 0.2 = s + (- 0.8)

- 7 (8 x - 13) - 34 = 15 x + 57

What are the solutions to the equation (50+3x^2)/5 =x^2 ?
The solutions to the equation (50+3x^2)/5 =x^2 are x=5,x=-5
Find the zeros of (50+3x^2)/5 =x^2
The zeros of (50+3x^2)/5 =x^2 are x=5,x=-5