What are the solutions to the equation x^2-29=0 ?

The solutions to the equation x^2-29=0 are x=sqrt(29),x=-sqrt(29)

Find the zeros of x^2-29=0

The zeros of x^2-29=0 are x=sqrt(29),x=-sqrt(29)

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x^{2} - 29 = 0

x = 29, x = - 29

Solution steps

x^{2} - 29 = 0

Move

29

to the right side

x^{2} = 29

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 29, x = - 29

e^{l o g_{e^{2}} (16)}

440 - [30 + 6 (19 - 12)]

\frac{\frac{x ^{2} - y ^{2}}{x y}}{\frac{1}{y} - \frac{1}{x}}

5 x + 2 (x + 1) \geq 23

2 x^{2} = 16

What are the solutions to the equation x^2-29=0 ?
The solutions to the equation x^2-29=0 are x=sqrt(29),x=-sqrt(29)
Find the zeros of x^2-29=0
The zeros of x^2-29=0 are x=sqrt(29),x=-sqrt(29)