What are the solutions to the equation 5x^2-7x+6=0 ?

The solutions to the equation 5x^2-7x+6=0 are x= 7/10+i(sqrt(71))/(10),x= 7/10-i(sqrt(71))/(10)

Find the zeros of 5x^2-7x+6=0

The zeros of 5x^2-7x+6=0 are x= 7/10+i(sqrt(71))/(10),x= 7/10-i(sqrt(71))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} - 7 x + 6 = 0

x = \frac{7}{10} + i \frac{71}{10}, x = \frac{7}{10} - i \frac{71}{10}

Solution steps

5 x^{2} - 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

Simplify

(- 7)^{2} - 4 \cdot 5 \cdot 6 : 71 i

x_{1, 2} = \frac{- ( - 7 ) \pm 71 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 71 i}{2 \cdot 5}, x_{2} = \frac{- ( - 7 ) - 71 i}{2 \cdot 5}

x = \frac{- ( - 7 ) + 71 i}{2 \cdot 5} : \frac{7}{10} + i \frac{71}{10}

x = \frac{- ( - 7 ) - 71 i}{2 \cdot 5} : \frac{7}{10} - i \frac{71}{10}

The solutions to the quadratic equation are:

x = \frac{7}{10} + i \frac{71}{10}, x = \frac{7}{10} - i \frac{71}{10}

(- 2)^{6} < 2^{8}

6 a + 4 a^{2}

5^{(\frac{1}{2})}

- \frac{π}{\frac{2}{2}}

(4 x y - \frac{1}{8} y^{2})^{2}

What are the solutions to the equation 5x^2-7x+6=0 ?
The solutions to the equation 5x^2-7x+6=0 are x= 7/10+i(sqrt(71))/(10),x= 7/10-i(sqrt(71))/(10)
Find the zeros of 5x^2-7x+6=0
The zeros of 5x^2-7x+6=0 are x= 7/10+i(sqrt(71))/(10),x= 7/10-i(sqrt(71))/(10)