What are the solutions to the equation 4-3x-x^2=2x+8 ?

The solutions to the equation 4-3x-x^2=2x+8 are x=-4,x=-1

Find the zeros of 4-3x-x^2=2x+8

The zeros of 4-3x-x^2=2x+8 are x=-4,x=-1

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4 - 3 x - x^{2} = 2 x + 8

x = - 4, x = - 1

Solution steps

4 - 3 x - x^{2} = 2 x + 8

Move

8

to the left side

- x^{2} - 3 x - 4 = 2 x

Move

2 x

to the left side

- x^{2} - 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

(- 5)^{2} - 4 (- 1) (- 4) = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 ( - 1 )}, x_{2} = \frac{- ( - 5 ) - 3}{2 ( - 1 )}

x = \frac{- ( - 5 ) + 3}{2 ( - 1 )} : - 4

x = \frac{- ( - 5 ) - 3}{2 ( - 1 )} : - 1

The solutions to the quadratic equation are:

x = - 4, x = - 1

7^{2} + 3^{2} = c^{2}

∣ 3 x - 1 ∣ = 8

(x + 5)^{2} + 4 = 68

∣ 10 + 4 x ∣ < 14

\frac{2 - 4 i}{8 i}

What are the solutions to the equation 4-3x-x^2=2x+8 ?
The solutions to the equation 4-3x-x^2=2x+8 are x=-4,x=-1
Find the zeros of 4-3x-x^2=2x+8
The zeros of 4-3x-x^2=2x+8 are x=-4,x=-1