What are the solutions to the equation 0=3x^2-3x ?

The solutions to the equation 0=3x^2-3x are x=1,x=0

Find the zeros of 0=3x^2-3x

The zeros of 0=3x^2-3x are x=1,x=0

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0 = 3 x^{2} - 3 x

x = 1, x = 0

Solution steps

0 = 3 x^{2} - 3 x

Switch sides

3 x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 3)^{2} - 4 \cdot 3 \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 3}, x_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 3}

x = \frac{- ( - 3 ) + 3}{2 \cdot 3} : 1

x = \frac{- ( - 3 ) - 3}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

x^{2} \leq 1

- \frac{h}{3} - 4 = 13

9 x^{2} + 30 x + 25

(\frac{5}{4})^{4}

7 x + \frac{1}{3} = 1

What are the solutions to the equation 0=3x^2-3x ?
The solutions to the equation 0=3x^2-3x are x=1,x=0
Find the zeros of 0=3x^2-3x
The zeros of 0=3x^2-3x are x=1,x=0