What are the solutions to the equation 0.05=(1+r/2)^2-1 ?

The solutions to the equation 0.05=(1+r/2)^2-1 are r=0.04939…,r=-4.04939…

Find the zeros of 0.05=(1+r/2)^2-1

The zeros of 0.05=(1+r/2)^2-1 are r=0.04939…,r=-4.04939…

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0.05 = (1 + \frac{r}{2})^{2} - 1

r = 0.04939 \dots, r = - 4.04939 \dots

Solution steps

0.05 = (1 + \frac{r}{2})^{2} - 1

Switch sides

(1 + \frac{r}{2})^{2} - 1 = 0.05

Move

1

to the right side

(1 + \frac{r}{2})^{2} = 1.05

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 + \frac{r}{2} = 1.05 : r = 0.04939 \dots

Solve

1 + \frac{r}{2} = - 1.05 : r = - 4.04939 \dots

The solutions to the quadratic equation are:

r = 0.04939 \dots, r = - 4.04939 \dots

- x^{2} + 4 x - 7 < 0

5 6^{2}

x^{2} + 21 x + 110

x^{2} - 49 < 0

x^{2} = - 1225

What are the solutions to the equation 0.05=(1+r/2)^2-1 ?
The solutions to the equation 0.05=(1+r/2)^2-1 are r=0.04939…,r=-4.04939…
Find the zeros of 0.05=(1+r/2)^2-1
The zeros of 0.05=(1+r/2)^2-1 are r=0.04939…,r=-4.04939…