What are the solutions to the equation 2x^2-9x+4=0 ?

The solutions to the equation 2x^2-9x+4=0 are x=4,x= 1/2

Find the zeros of 2x^2-9x+4=0

The zeros of 2x^2-9x+4=0 are x=4,x= 1/2

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2 x^{2} - 9 x + 4 = 0

x = 4, x = \frac{1}{2}

Solution steps

2 x^{2} - 9 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 \cdot 4}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 \cdot 4 = 7

x_{1, 2} = \frac{- ( - 9 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 7}{2 \cdot 2}

x = \frac{- ( - 9 ) + 7}{2 \cdot 2} : 4

x = \frac{- ( - 9 ) - 7}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 4, x = \frac{1}{2}

- 4 - 5

4 p^{3} + 8 p^{2} + 3 p + 6

1 - \frac{x + 2}{3} = x

\frac{5 + 4 i}{5 - 6 i}

What are the solutions to the equation 2x^2-9x+4=0 ?
The solutions to the equation 2x^2-9x+4=0 are x=4,x= 1/2
Find the zeros of 2x^2-9x+4=0
The zeros of 2x^2-9x+4=0 are x=4,x= 1/2