What are the solutions to the equation 4m^2+76=0 ?

The solutions to the equation 4m^2+76=0 are m=sqrt(19)i,m=-sqrt(19)i

Find the zeros of 4m^2+76=0

The zeros of 4m^2+76=0 are m=sqrt(19)i,m=-sqrt(19)i

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4 m^{2} + 76 = 0

m = 19 i, m = - 19 i

Solution steps

4 m^{2} + 76 = 0

Move

76

to the right side

4 m^{2} = - 76

Divide both sides by

4

m^{2} = - 19

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = - 19, m = - - 19

- 19 = 19 i

- - 19 = - 19 i

m = 19 i, m = - 19 i

3 y = 3

\frac{( x ^{2} y ^{3} ) ( x y ) ^{- 8}}{x ^{2} y}

\frac{2 n - 8}{n ^{2} - 16}

(\frac{1}{3})^{- 0}

5 \cdot (a + 3)^{2} - (a + 3)

What are the solutions to the equation 4m^2+76=0 ?
The solutions to the equation 4m^2+76=0 are m=sqrt(19)i,m=-sqrt(19)i
Find the zeros of 4m^2+76=0
The zeros of 4m^2+76=0 are m=sqrt(19)i,m=-sqrt(19)i