What are the solutions to the equation 4(x-3)^2-64=0 ?

The solutions to the equation 4(x-3)^2-64=0 are x=7,x=-1

Find the zeros of 4(x-3)^2-64=0

The zeros of 4(x-3)^2-64=0 are x=7,x=-1

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4 (x - 3)^{2} - 64 = 0

x = 7, x = - 1

Solution steps

4 (x - 3)^{2} - 64 = 0

Move

64

to the right side

4 (x - 3)^{2} = 64

Divide both sides by

4

(x - 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 16 : x = 7

Solve

x - 3 = - 16 : x = - 1

The solutions to the quadratic equation are:

x = 7, x = - 1

(4 - 23)^{2}

- \frac{1}{- 7}

7 x - 4 - 3 x = - 44

\frac{4}{5} + 1

6 - 3 x = 6 - 2.5 x

What are the solutions to the equation 4(x-3)^2-64=0 ?
The solutions to the equation 4(x-3)^2-64=0 are x=7,x=-1
Find the zeros of 4(x-3)^2-64=0
The zeros of 4(x-3)^2-64=0 are x=7,x=-1