What are the solutions to the equation 6x^2+4x-1=0 ?

The solutions to the equation 6x^2+4x-1=0 are x=(-2+sqrt(10))/6 ,x=-(2+sqrt(10))/6

Find the zeros of 6x^2+4x-1=0

The zeros of 6x^2+4x-1=0 are x=(-2+sqrt(10))/6 ,x=-(2+sqrt(10))/6

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6 x^{2} + 4 x - 1 = 0

x = \frac{- 2 + 10}{6}, x = - \frac{2 + 10}{6}

Decimal Notation

x = 0.19371 \dots, x = - 0.86037 \dots

Solution steps

6 x^{2} + 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

4^{2} - 4 \cdot 6 (- 1) = 210

x_{1, 2} = \frac{- 4 \pm 2 10}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 4 + 2 10}{2 \cdot 6}, x_{2} = \frac{- 4 - 2 10}{2 \cdot 6}

x = \frac{- 4 + 2 10}{2 \cdot 6} : \frac{- 2 + 10}{6}

x = \frac{- 4 - 2 10}{2 \cdot 6} : - \frac{2 + 10}{6}

The solutions to the quadratic equation are:

x = \frac{- 2 + 10}{6}, x = - \frac{2 + 10}{6}

x^{2} + 4 x = 96

4 x^{2} = 22 x + 42

3 x - \frac{5}{2} > \frac{1}{2} x

40 - 454 i

d + 9 = 15

What are the solutions to the equation 6x^2+4x-1=0 ?
The solutions to the equation 6x^2+4x-1=0 are x=(-2+sqrt(10))/6 ,x=-(2+sqrt(10))/6
Find the zeros of 6x^2+4x-1=0
The zeros of 6x^2+4x-1=0 are x=(-2+sqrt(10))/6 ,x=-(2+sqrt(10))/6