What are the solutions to the equation 4x^2=22x+42 ?

The solutions to the equation 4x^2=22x+42 are x=7,x=-3/2

Find the zeros of 4x^2=22x+42

The zeros of 4x^2=22x+42 are x=7,x=-3/2

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4 x^{2} = 22 x + 42

x = 7, x = - \frac{3}{2}

Decimal Notation

x = 7, x = - 1.5

Solution steps

4 x^{2} = 22 x + 42

Move

42

to the left side

4 x^{2} - 42 = 22 x

Move

22 x

to the left side

4 x^{2} - 42 - 22 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 22 x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 4 ( - 42 )}{2 \cdot 4}

(- 22)^{2} - 4 \cdot 4 (- 42) = 34

x_{1, 2} = \frac{- ( - 22 ) \pm 34}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 34}{2 \cdot 4}, x_{2} = \frac{- ( - 22 ) - 34}{2 \cdot 4}

x = \frac{- ( - 22 ) + 34}{2 \cdot 4} : 7

x = \frac{- ( - 22 ) - 34}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 7, x = - \frac{3}{2}

3 x - \frac{5}{2} > \frac{1}{2} x

40 - 454 i

d + 9 = 15

s^{2} = 52

4 - w^{2}

What are the solutions to the equation 4x^2=22x+42 ?
The solutions to the equation 4x^2=22x+42 are x=7,x=-3/2
Find the zeros of 4x^2=22x+42
The zeros of 4x^2=22x+42 are x=7,x=-3/2