What are the solutions to the equation 31p^2+10p+1=6p^2 ?

The solutions to the equation 31p^2+10p+1=6p^2 are p=-1/5

Find the zeros of 31p^2+10p+1=6p^2

The zeros of 31p^2+10p+1=6p^2 are p=-1/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

31 p^{2} + 10 p + 1 = 6 p^{2}

p = - \frac{1}{5}

Decimal Notation

p = - 0.2

Solution steps

31 p^{2} + 10 p + 1 = 6 p^{2}

Move

6 p^{2}

to the left side

25 p^{2} + 10 p + 1 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 25 \cdot 1}{2 \cdot 25}

1 0^{2} - 4 \cdot 25 \cdot 1 = 0

p_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 25}

p = \frac{- 10}{2 \cdot 25}

\frac{- 10}{2 \cdot 25} = - \frac{1}{5}

p = - \frac{1}{5}

The solution to the quadratic equation is:

p = - \frac{1}{5}

w (w + 2) = - 5

3 ∣ 9 b - 1 ∣ - 10 = - 10

∣ 3 x - 19 ∣ = - 11

- \frac{5}{9} + (- \frac{4}{3}) - \frac{2}{3}

\frac{9 - 2 k}{3} = k - 2

What are the solutions to the equation 31p^2+10p+1=6p^2 ?
The solutions to the equation 31p^2+10p+1=6p^2 are p=-1/5
Find the zeros of 31p^2+10p+1=6p^2
The zeros of 31p^2+10p+1=6p^2 are p=-1/5