What are the solutions to the equation x^2=15x ?

The solutions to the equation x^2=15x are x=15,x=0

Find the zeros of x^2=15x

The zeros of x^2=15x are x=15,x=0

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x^{2} = 15 x

x = 15, x = 0

Solution steps

x^{2} = 15 x

Move

15 x

to the left side

x^{2} - 15 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 0 = 15

x_{1, 2} = \frac{- ( - 15 ) \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 15}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 15}{2 \cdot 1}

x = \frac{- ( - 15 ) + 15}{2 \cdot 1} : 15

x = \frac{- ( - 15 ) - 15}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 15, x = 0

\frac{2}{5}

f (a) = \frac{a ^{2} + a - 42}{a ^{2} - a - 30}

x^{2} - 12 = 11 x

3 x + 5 > - 1 or - 2 x - 7 > 5

6 x = 1

What are the solutions to the equation x^2=15x ?
The solutions to the equation x^2=15x are x=15,x=0
Find the zeros of x^2=15x
The zeros of x^2=15x are x=15,x=0