en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 8y^6+27

Solution

factor

8 y^{6} + 27

Solution

(2 y^{2} + 3) (4 y^{4} - 6 y^{2} + 9)

Solution steps

8 y^{6} + 27

Apply exponent rules

= (2 y^{2})^{3} + 3^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(2 y^{2})^{3} + 3^{3} = (2 y^{2} + 3) (2^{2} y^{4} - 3 \cdot 2 y^{2} + 3^{2})

= (2 y^{2} + 3) (2^{2} y^{4} - 3 \cdot 2 y^{2} + 3^{2})

Simplify

(2 y^{2} + 3) (2^{2} y^{4} - 3 \cdot 2 y^{2} + 3^{2}) : (2 y^{2} + 3) (4 y^{4} - 6 y^{2} + 9)

= (2 y^{2} + 3) (4 y^{4} - 6 y^{2} + 9)

Popular Examples

factor 2x^3-19x+3 factor

2 x^{3} - 19 x + 3

factor a^4-25a^2+144 factor

a^{4} - 25 a^{2} + 144

(16x}{16}=\frac{8*8*5)/5

\frac{16 x}{16} = \frac{8 \cdot 8 \cdot 5}{5}

factor 18x^2-9x-2 factor

18 x^{2} - 9 x - 2

x + 5 = 14 - \frac{1}{2} x

Frequently Asked Questions (FAQ)

What is factor 8y^6+27 ?
The solution to factor 8y^6+27 is (2y^2+3)(4y^4-6y^2+9)