What are the solutions to the equation (x+3)(x-3)=16-2x^2 ?

The solutions to the equation (x+3)(x-3)=16-2x^2 are x= 5/(sqrt(3)),x=-5/(sqrt(3))

Find the zeros of (x+3)(x-3)=16-2x^2

The zeros of (x+3)(x-3)=16-2x^2 are x= 5/(sqrt(3)),x=-5/(sqrt(3))

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(x + 3) (x - 3) = 16 - 2 x^{2}

x = \frac{5}{3}, x = - \frac{5}{3}

Solution steps

(x + 3) (x - 3) = 16 - 2 x^{2}

Expand

(x + 3) (x - 3) : x^{2} - 9

x^{2} - 9 = 16 - 2 x^{2}

Move

9

to the right side

x^{2} = - 2 x^{2} + 25

Move

2 x^{2}

to the left side

3 x^{2} = 25

Divide both sides by

3

x^{2} = \frac{25}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{3}, x = - \frac{25}{3}

\frac{25}{3} = \frac{5}{3}

- \frac{25}{3} = - \frac{5}{3}

x = \frac{5}{3}, x = - \frac{5}{3}

\frac{x - 1}{x - 3} < 0

3 x^{2} - 12 x + 12

\frac{( - 2 ) ^{3} \cdot 2 ^{- 4}}{2 ^{- 3}}

2 + \frac{1}{6}

6^{2} - 5 \cdot 6 - 3

What are the solutions to the equation (x+3)(x-3)=16-2x^2 ?
The solutions to the equation (x+3)(x-3)=16-2x^2 are x= 5/(sqrt(3)),x=-5/(sqrt(3))
Find the zeros of (x+3)(x-3)=16-2x^2
The zeros of (x+3)(x-3)=16-2x^2 are x= 5/(sqrt(3)),x=-5/(sqrt(3))