What are the solutions to the equation 0=x^2-12x-64 ?

The solutions to the equation 0=x^2-12x-64 are x=16,x=-4

Find the zeros of 0=x^2-12x-64

The zeros of 0=x^2-12x-64 are x=16,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{2} - 12 x - 64

x = 16, x = - 4

Solution steps

0 = x^{2} - 12 x - 64

Switch sides

x^{2} - 12 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 64 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 64) = 20

x_{1, 2} = \frac{- ( - 12 ) \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 20}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 20}{2 \cdot 1}

x = \frac{- ( - 12 ) + 20}{2 \cdot 1} : 16

x = \frac{- ( - 12 ) - 20}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 16, x = - 4

x^{3} + 4 x^{2}

\frac{a}{5} = \frac{a - 3}{2}

∣ 4 - 5 x ∣ + 8 = 13

x^{2} - 40 = 0

∣ 3 x - 2 ∣ < 9

What are the solutions to the equation 0=x^2-12x-64 ?
The solutions to the equation 0=x^2-12x-64 are x=16,x=-4
Find the zeros of 0=x^2-12x-64
The zeros of 0=x^2-12x-64 are x=16,x=-4