What are the solutions to the equation 3h^2+17h=-10 ?

The solutions to the equation 3h^2+17h=-10 are h=-2/3 ,h=-5

Find the zeros of 3h^2+17h=-10

The zeros of 3h^2+17h=-10 are h=-2/3 ,h=-5

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3 h^{2} + 17 h = - 10

h = - \frac{2}{3}, h = - 5

Decimal Notation

h = - 0.66666 \dots, h = - 5

Solution steps

3 h^{2} + 17 h = - 10

Move

10

to the left side

3 h^{2} + 17 h + 10 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 3 \cdot 10}{2 \cdot 3}

1 7^{2} - 4 \cdot 3 \cdot 10 = 13

h_{1, 2} = \frac{- 17 \pm 13}{2 \cdot 3}

Separate the solutions

h_{1} = \frac{- 17 + 13}{2 \cdot 3}, h_{2} = \frac{- 17 - 13}{2 \cdot 3}

h = \frac{- 17 + 13}{2 \cdot 3} : - \frac{2}{3}

h = \frac{- 17 - 13}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

h = - \frac{2}{3}, h = - 5

(\frac{x ^{2}}{4})^{2}

3 (3 x - 3) = 27

4 x - 8 = 6 x + 12

- 9 q - 6 \geq - 2 q - 10

\frac{2}{4}

What are the solutions to the equation 3h^2+17h=-10 ?
The solutions to the equation 3h^2+17h=-10 are h=-2/3 ,h=-5
Find the zeros of 3h^2+17h=-10
The zeros of 3h^2+17h=-10 are h=-2/3 ,h=-5