What are the solutions to the equation 9x^2-18x+9=0 ?

The solutions to the equation 9x^2-18x+9=0 are x=1

Find the zeros of 9x^2-18x+9=0

The zeros of 9x^2-18x+9=0 are x=1

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9 x^{2} - 18 x + 9 = 0

x = 1

Solution steps

9 x^{2} - 18 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 \cdot 9}{2 \cdot 9}

(- 18)^{2} - 4 \cdot 9 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 18 ) \pm 0}{2 \cdot 9}

x = \frac{- ( - 18 )}{2 \cdot 9}

\frac{- ( - 18 )}{2 \cdot 9} = 1

x = 1

The solution to the quadratic equation is:

x = 1

\frac{( \frac{1}{x} + \frac{1}{y} )}{x - y}

∣ 4 x ∣ > 28

- 2 x - 11 \leq - 31

\frac{1}{6 ^{5}}

30 x^{3} + 15 x^{4}

What are the solutions to the equation 9x^2-18x+9=0 ?
The solutions to the equation 9x^2-18x+9=0 are x=1
Find the zeros of 9x^2-18x+9=0
The zeros of 9x^2-18x+9=0 are x=1