What are the solutions to the equation (x+1)^2=-3 ?

The solutions to the equation (x+1)^2=-3 are x=sqrt(3)i-1,x=-sqrt(3)i-1

Find the zeros of (x+1)^2=-3

The zeros of (x+1)^2=-3 are x=sqrt(3)i-1,x=-sqrt(3)i-1

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(x + 1)^{2} = - 3

x = 3 i - 1, x = - 3 i - 1

Solution steps

(x + 1)^{2} = - 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = - 3 : x = 3 i - 1

Solve

x + 1 = - - 3 : x = - 3 i - 1

The solutions to the quadratic equation are:

x = 3 i - 1, x = - 3 i - 1

\frac{( 2 x - 3 ) ( 3 x + 8 )}{( x - 8 ) ^{3}} \geq 0

- 4 \leq 5 x + 13 < 23

\frac{8 i}{4 - 3 i}

5 n^{2} + 12 n + 7

\frac{5 x}{x - 5} < 1

What are the solutions to the equation (x+1)^2=-3 ?
The solutions to the equation (x+1)^2=-3 are x=sqrt(3)i-1,x=-sqrt(3)i-1
Find the zeros of (x+1)^2=-3
The zeros of (x+1)^2=-3 are x=sqrt(3)i-1,x=-sqrt(3)i-1