What are the solutions to the equation 2x^2-6x+10=-3x+9 ?

The solutions to the equation 2x^2-6x+10=-3x+9 are x=1,x= 1/2

Find the zeros of 2x^2-6x+10=-3x+9

The zeros of 2x^2-6x+10=-3x+9 are x=1,x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 6 x + 10 = - 3 x + 9

x = 1, x = \frac{1}{2}

Solution steps

2 x^{2} - 6 x + 10 = - 3 x + 9

Move

9

to the left side

2 x^{2} - 6 x + 1 = - 3 x

Move

3 x

to the left side

2 x^{2} - 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 \cdot 1 = 1

x_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 2}

x = \frac{- ( - 3 ) + 1}{2 \cdot 2} : 1

x = \frac{- ( - 3 ) - 1}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{2}

4 (2 d + 5) - 8 = 36

4 x^{3} - 3 x

\frac{2}{3} x - \frac{1}{2} = x + \frac{3}{4}

2 x + 5 > x + 2

x^{2} + 4 x - 12 > 0

What are the solutions to the equation 2x^2-6x+10=-3x+9 ?
The solutions to the equation 2x^2-6x+10=-3x+9 are x=1,x= 1/2
Find the zeros of 2x^2-6x+10=-3x+9
The zeros of 2x^2-6x+10=-3x+9 are x=1,x= 1/2