What is factor 27a^3+b^6 ?

The solution to factor 27a^3+b^6 is (3a+b^2)(9a^2-3ab^2+b^4)

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factor 27a^3+b^6

factor

27 a^{3} + b^{6}

(3 a + b^{2}) (9 a^{2} - 3 a b^{2} + b^{4})

Solution steps

27 a^{3} + b^{6}

Apply exponent rules

= (3 a)^{3} + (b^{2})^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(3 a)^{3} + (b^{2})^{3} = (3 a + b^{2}) ((3 a)^{2} - 3 a b^{2} + (b^{2})^{2})

= (3 a + b^{2}) ((3 a)^{2} - 3 a b^{2} + (b^{2})^{2})

Simplify

(3 a)^{2} - 3 a b^{2} + (b^{2})^{2} : 9 a^{2} - 3 a b^{2} + b^{4}

= (3 a + b^{2}) (9 a^{2} - 3 a b^{2} + b^{4})

- 12 x^{5} y^{5} (- 12 x^{3} y^{3})

- 10 (\frac{2}{5})^{3}

\frac{9}{x y} + \frac{x ^{2}}{y}

(\frac{( 1.72 \cdot 65 )}{175.75})^{- 7.69}

5 x + 6 = 2 x + 15

What is factor 27a^3+b^6 ?
The solution to factor 27a^3+b^6 is (3a+b^2)(9a^2-3ab^2+b^4)