What are the solutions to the equation x^2=72-x ?

The solutions to the equation x^2=72-x are x=8,x=-9

Find the zeros of x^2=72-x

The zeros of x^2=72-x are x=8,x=-9

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x^{2} = 72 - x

x = 8, x = - 9

Solution steps

x^{2} = 72 - x

Move

x

to the left side

x^{2} + x = 72

Move

72

to the left side

x^{2} + x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 72) = 17

x_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 17}{2 \cdot 1}, x_{2} = \frac{- 1 - 17}{2 \cdot 1}

x = \frac{- 1 + 17}{2 \cdot 1} : 8

x = \frac{- 1 - 17}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 8, x = - 9

8 d - 11 + 3 d + 2 = 13

\frac{m ^{2} + 5 m + 6}{m ^{2} - 4} + \frac{2}{m - 2}

\frac{1}{a ^{2} b ^{- 3}} (a^{2} b^{- 3})^{- 1}

2 (3 - 5 x) > 18 - 8 x

\frac{1}{15}

What are the solutions to the equation x^2=72-x ?
The solutions to the equation x^2=72-x are x=8,x=-9
Find the zeros of x^2=72-x
The zeros of x^2=72-x are x=8,x=-9