What are the solutions to the equation x^2-18x+61=0 ?

The solutions to the equation x^2-18x+61=0 are x=9+2sqrt(5),x=9-2sqrt(5)

Find the zeros of x^2-18x+61=0

The zeros of x^2-18x+61=0 are x=9+2sqrt(5),x=9-2sqrt(5)

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x^{2} - 18 x + 61 = 0

x = 9 + 25, x = 9 - 25

Solution steps

x^{2} - 18 x + 61 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 61}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 61 = 45

x_{1, 2} = \frac{- ( - 18 ) \pm 4 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 4 5}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 4 5}{2 \cdot 1}

x = \frac{- ( - 18 ) + 4 5}{2 \cdot 1} : 9 + 25

x = \frac{- ( - 18 ) - 4 5}{2 \cdot 1} : 9 - 25

The solutions to the quadratic equation are:

x = 9 + 25, x = 9 - 25

\frac{q ^{5} r}{4} - \frac{q}{5}

9 x = 90

\frac{3 + \frac{2}{3}}{\frac{1}{4} + \frac{5}{12}} - \frac{5}{8} - \frac{5}{6}

- 252

- 17 = n - 6

What are the solutions to the equation x^2-18x+61=0 ?
The solutions to the equation x^2-18x+61=0 are x=9+2sqrt(5),x=9-2sqrt(5)
Find the zeros of x^2-18x+61=0
The zeros of x^2-18x+61=0 are x=9+2sqrt(5),x=9-2sqrt(5)