What are the solutions to the equation 25x^2+1=5 ?

The solutions to the equation 25x^2+1=5 are x= 2/5 ,x=-2/5

Find the zeros of 25x^2+1=5

The zeros of 25x^2+1=5 are x= 2/5 ,x=-2/5

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25 x^{2} + 1 = 5

x = \frac{2}{5}, x = - \frac{2}{5}

Solution steps

25 x^{2} + 1 = 5

Move

1

to the right side

25 x^{2} = 4

Divide both sides by

25

x^{2} = \frac{4}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{25}, x = - \frac{4}{25}

\frac{4}{25} = \frac{2}{5}

- \frac{4}{25} = - \frac{2}{5}

x = \frac{2}{5}, x = - \frac{2}{5}

y^{2} - 4 (- 2) - 4 y - 12 = 0

- 4 + x = - 11

- 7 < 2 x + 4 < 8

7 x = 21

2 t^{2} + 1 = 0

What are the solutions to the equation 25x^2+1=5 ?
The solutions to the equation 25x^2+1=5 are x= 2/5 ,x=-2/5
Find the zeros of 25x^2+1=5
The zeros of 25x^2+1=5 are x= 2/5 ,x=-2/5