What is (2x^2y^4*4x^2y^4*3x)/(3x^{-3)y^2} ?

The solution to (2x^2y^4*4x^2y^4*3x)/(3x^{-3)y^2} is 8x^8y^6

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simplify (2x^2y^44x^2y^43x)/(3x^{-3)y^2}

simplify

\frac{2 x ^{2} y ^{4} \cdot 4 x ^{2} y ^{4} \cdot 3 x}{3 x ^{- 3} y ^{2}}

8 x^{8} y^{6}

Solution steps

\frac{2 x ^{2} y ^{4} \cdot 4 x ^{2} y ^{4} \cdot 3 x}{3 x ^{- 3} y ^{2}}

Cancel the common factor:

3

= \frac{2 x ^{2} y ^{4} \cdot 4 x ^{2} y ^{4} x}{x ^{- 3} y ^{2}}

Simplify

\frac{x ^{2}}{x ^{- 3}} : x^{5}

= \frac{2 x ^{5} y ^{4} \cdot 4 x ^{2} y ^{4} x}{y ^{2}}

Simplify

\frac{y ^{4}}{y ^{2}} : y^{2}

= 2 x^{5} y^{2} \cdot 4 x^{2} y^{4} x

Simplify

2 x^{5} y^{2} \cdot 4 x^{2} y^{4} x : 8 x^{8} y^{6}

= 8 x^{8} y^{6}

2 x^{2} + 10 x + 11 = 0

\frac{4}{5} x = - 2

lo g_{4} (5) x^{2} + lo g_{4} (5) = 1

2 a^{0}

5 m^{2} - 43 m - 18 = 0

What is (2x^2y^4*4x^2y^4*3x)/(3x^{-3)y^2} ?
The solution to (2x^2y^4*4x^2y^4*3x)/(3x^{-3)y^2} is 8x^8y^6