What are the solutions to the equation 4x^2+17x+15=0 ?

The solutions to the equation 4x^2+17x+15=0 are x=-5/4 ,x=-3

Find the zeros of 4x^2+17x+15=0

The zeros of 4x^2+17x+15=0 are x=-5/4 ,x=-3

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4 x^{2} + 17 x + 15 = 0

x = - \frac{5}{4}, x = - 3

Solution steps

4 x^{2} + 17 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 4 \cdot 15}{2 \cdot 4}

1 7^{2} - 4 \cdot 4 \cdot 15 = 7

x_{1, 2} = \frac{- 17 \pm 7}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 17 + 7}{2 \cdot 4}, x_{2} = \frac{- 17 - 7}{2 \cdot 4}

x = \frac{- 17 + 7}{2 \cdot 4} : - \frac{5}{4}

x = \frac{- 17 - 7}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = - \frac{5}{4}, x = - 3

\frac{x}{2} - \frac{x}{3} = \frac{x}{6}

- 7 y \geq - 21

\frac{9 !}{( 9 - 2 ) ! 2 !}

- x^{2} + 12 x - 35 = 0

3 (\frac{5}{2}) - 2 y + 2 = 0

What are the solutions to the equation 4x^2+17x+15=0 ?
The solutions to the equation 4x^2+17x+15=0 are x=-5/4 ,x=-3
Find the zeros of 4x^2+17x+15=0
The zeros of 4x^2+17x+15=0 are x=-5/4 ,x=-3