What are the solutions to the equation (x-4)(x+7)=0 ?

The solutions to the equation (x-4)(x+7)=0 are x=4,x=-7

Find the zeros of (x-4)(x+7)=0

The zeros of (x-4)(x+7)=0 are x=4,x=-7

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(x - 4) (x + 7) = 0

x = 4, x = - 7

Solution steps

(x - 4) (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x + 7 = 0

Solve

x - 4 = 0 : x = 4

Solve

x + 7 = 0 : x = - 7

The solutions to the quadratic equation are:

x = 4, x = - 7

x^{2} - 8 \geq 0

8 x^{9} + 27 y^{15}

x^{2} + 4 x = 140

x = x^{2} - 6 x + 5

198

What are the solutions to the equation (x-4)(x+7)=0 ?
The solutions to the equation (x-4)(x+7)=0 are x=4,x=-7
Find the zeros of (x-4)(x+7)=0
The zeros of (x-4)(x+7)=0 are x=4,x=-7