What is p/q x^4+2x^3-5x^2-x+6 ?

The solution to p/q x^4+2x^3-5x^2-x+6 is (px^4)/q+2x^3-5x^2-x+6

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simplify p/q x^4+2x^3-5x^2-x+6

simplify

\frac{p}{q} x^{4} + 2 x^{3} - 5 x^{2} - x + 6

\frac{p x ^{4}}{q} + 2 x^{3} - 5 x^{2} - x + 6

Solution steps

\frac{p}{q} x^{4} + 2 x^{3} - 5 x^{2} - x + 6

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

\frac{p}{q} x^{4} = \frac{p x ^{4}}{q}

= \frac{p x ^{4}}{q} + 2 x^{3} - 5 x^{2} - x + 6

3 (x^{2} - 1) = 0

∣ x - 32 ∣ < 2

\frac{- 1000}{- 1000 - 4}

(x y)^{3} (8 x^{2} y^{3})^{2}

\frac{3 x ^{- 3} y ^{3}}{3 x ^{- 3} y ^{- 1} \cdot ( 3 x ^{- 1} y ^{- 2} ) ^{- 3}}

What is p/q x^4+2x^3-5x^2-x+6 ?
The solution to p/q x^4+2x^3-5x^2-x+6 is (px^4)/q+2x^3-5x^2-x+6