What are the solutions to the equation 2m^2+5m+2=0 ?

The solutions to the equation 2m^2+5m+2=0 are m=-1/2 ,m=-2

Find the zeros of 2m^2+5m+2=0

The zeros of 2m^2+5m+2=0 are m=-1/2 ,m=-2

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2 m^{2} + 5 m + 2 = 0

m = - \frac{1}{2}, m = - 2

Solution steps

2 m^{2} + 5 m + 2 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

5^{2} - 4 \cdot 2 \cdot 2 = 3

m_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- 5 + 3}{2 \cdot 2}, m_{2} = \frac{- 5 - 3}{2 \cdot 2}

m = \frac{- 5 + 3}{2 \cdot 2} : - \frac{1}{2}

m = \frac{- 5 - 3}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

m = - \frac{1}{2}, m = - 2

4 x^{2} - 2 < 0

\frac{3 - 2 x}{5} = \frac{4 x + 1}{3}

x^{4} + 5 x^{2} \geq 36

5.5 x = (4.47 x - 10000)^{2}

7 x^{2} = 16

What are the solutions to the equation 2m^2+5m+2=0 ?
The solutions to the equation 2m^2+5m+2=0 are m=-1/2 ,m=-2
Find the zeros of 2m^2+5m+2=0
The zeros of 2m^2+5m+2=0 are m=-1/2 ,m=-2