What are the solutions to the equation (x+3)^2+25=0 ?

The solutions to the equation (x+3)^2+25=0 are x=5i-3,x=-5i-3

Find the zeros of (x+3)^2+25=0

The zeros of (x+3)^2+25=0 are x=5i-3,x=-5i-3

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(x + 3)^{2} + 25 = 0

x = 5 i - 3, x = - 5 i - 3

Solution steps

(x + 3)^{2} + 25 = 0

Move

25

to the right side

(x + 3)^{2} = - 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = - 25 : x = 5 i - 3

Solve

x + 3 = - - 25 : x = - 5 i - 3

The solutions to the quadratic equation are:

x = 5 i - 3, x = - 5 i - 3

8^{\frac{4}{3}}

\frac{( x ^{3} + y ^{3} )}{( x - y )}

lo g_{2} (36) - 2 lo g_{2} (3)

\frac{x + 3}{x - 2} \leq 0

What are the solutions to the equation (x+3)^2+25=0 ?
The solutions to the equation (x+3)^2+25=0 are x=5i-3,x=-5i-3
Find the zeros of (x+3)^2+25=0
The zeros of (x+3)^2+25=0 are x=5i-3,x=-5i-3