What are the solutions to the equation 6x^2-x-12=0 ?

The solutions to the equation 6x^2-x-12=0 are x= 3/2 ,x=-4/3

Find the zeros of 6x^2-x-12=0

The zeros of 6x^2-x-12=0 are x= 3/2 ,x=-4/3

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6 x^{2} - x - 12 = 0

x = \frac{3}{2}, x = - \frac{4}{3}

Decimal Notation

x = 1.5, x = - 1.33333 \dots

Solution steps

6 x^{2} - x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 6 ( - 12 )}{2 \cdot 6}

(- 1)^{2} - 4 \cdot 6 (- 12) = 17

x_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 6}, x_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 6}

x = \frac{- ( - 1 ) + 17}{2 \cdot 6} : \frac{3}{2}

x = \frac{- ( - 1 ) - 17}{2 \cdot 6} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{4}{3}

- 3 + 2 c \geq 5

100000 (1.05)^{2}

\frac{2}{5} (x - 7) = \frac{3}{4} (4 x - 3)

9 x^{2} - 12 x - 5

2 x^{2} - 11 x + 15

What are the solutions to the equation 6x^2-x-12=0 ?
The solutions to the equation 6x^2-x-12=0 are x= 3/2 ,x=-4/3
Find the zeros of 6x^2-x-12=0
The zeros of 6x^2-x-12=0 are x= 3/2 ,x=-4/3