What is the answer to (3-2x)/2+(x+2)/3 =3 ?

The answer to (3-2x)/2+(x+2)/3 =3 is x=-5/4

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(3-2x)/2+(x+2)/3 =3

\frac{3 - 2 x}{2} + \frac{x + 2}{3} = 3

x = - \frac{5}{4}

Solution steps

\frac{3 - 2 x}{2} + \frac{x + 2}{3} = 3

Multiply by LCM

3 (- 2 x + 3) + 2 (x + 2) = 18

Expand

3 (- 2 x + 3) + 2 (x + 2) : - 4 x + 13

- 4 x + 13 = 18

Move

13

to the right side

- 4 x = 5

Divide both sides by

- 4

x = - \frac{5}{4}

y^{3} - 216

9 x^{2} - 25 y^{2} + 10 y - 1

2 m^{2} \cdot 2 m^{3}

(x - 1) (x + 1) \leq 0

- 3 (\frac{1}{6} y) - 18 = 72

What is the answer to (3-2x)/2+(x+2)/3 =3 ?
The answer to (3-2x)/2+(x+2)/3 =3 is x=-5/4
Solve for x: (3-2x)/2+(x+2)/3 =3
The solution is x=-5/4